To divide a line segment AB in the ratio p : q ( p, q are positive integers), draw a ray AX so that ∠BAX s an acute angle and then mark points on ray AX at equal distances such that the minimum number of these points is :
According to the question, the minimum number of those points which are to be marked should be (Numerator + Denominator) i.e., p + q
To divide a line segment AB in the ration 2 : 5, first a ray AX is drawn, so that ∠BAX is an acute angle and then at equal distances points are marked on the ray such that the minimum number of these points is :
According to the question, the minimum number of those points which are to be marked should be (Numerator + Denominator) i.e. , 2 + 5 = 7
To divide a line segment PQ in the ratio 2 : 7, first a ray PZ is drawn so that ∠QPX is an acute angle and then at equal distances points are marked on the ray PX such that the minimum number of these points is :
According to the question, the minimum number of those points which are to be marked should be (Numerator + Denominator) i.e., 2 + 7 = 9
To divide a line segment LM in the ratio a : b, where a and b are positive integers, draw a ray LX so that ∠MLX is an acute angle and then mark points on the ray LX at equal distances such that the minimum number of these points is :
According to the question, the minimum number of those points which are to be marked should be (Numerator + Denominator) i.e., a + b
To construct a triangle similar to given ΔABC with its sides 7/4 of the corresponding sides of ΔABC, draw a ray BX such that ∠CBX is an acute angle and X is on the opposite side of A with respect to BC. The minimum number of points to be located at equal distances on ray BX is :
When numerator is greater than denominator, then number of arcs should be drawn larger of m and n. Therefore, according to question, the minimum number of points to be located at equal distances on ray BX is 7.